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England announce playing XI for first Test against India

The much-awaited first match of the five-match Test series between India and England is going to be played tomorrow. According to their own rules, England announced the eleven on the day before the match.

England announce playing XI for first Test against India

Posted - 2024-01-24T17:11:38+06:00

Updated - 2024-01-26T10:15:09+06:00

England are entering the field in the Hyderabad Test against India by increasing the strength of the spin department. There are 3 specialist spinners in England's announced XI on the eve of the match. Mark Wood is the only pacer to get a place in the XI. 

The much-awaited first match of the five-match Test series between India and England is going to be played tomorrow. According to their own rules, England announced the eleven on the day before the match. Mark Wood is the only pacer in the XI along with three spinners Jack Leach, Tom Hartley and Rehan Ahmed. Meanwhile, Hartley is going to get a taste of Test debut. James Anderson did not get a place in the XI due to the power of spin.

The rest of the places are expected. Ben Foakes returns to the playing XI as a wicket-keeper batter. As a result, Jonny Bairstow will play at No. 5. Zak Crawley is joined by Ben Duckett as usual in the opening. Ollie Pope will play at No. 3 and Joe Root at No. 4. Skipper Ben Stokes is at No. 6 and Foakes is at No. 7 with the keeping gloves.

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Then there is Rehan, Wood, Hartley, and Leach as usual. On the other hand, India have not lost a Test series at home since 2012. The whole cricket world is looking forward to enjoy the fight between the two teams. 

Tomorrow, the first Test match between the two teams will be played at the Rajiv Gandhi International Stadium in Hyderabad at 10 am Bangladesh time.

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England XI: Zak Crawley, Ben Duckett, Ollie Pope, Joe Root, Jonny Bairstow, Ben Stokes (c), Ben Foakes, Rehan Ahmed, Tom Hartley, Mark Wood, Jack Leach.

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